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in #math7 years ago

Here’s a curious way to split a product of two integers into two summands:

n · (b - 1) = (n - 1) · b + (b - n)

For example, for n=3 and b=10,

3 · 9 = 2 · 10 + 7

Now since we can consider

(n - 1) · 1 + (b - n) = b - 1

where the n cancels out on the right hand side, we have the following

Take care
@qed

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I believe you but I still want the proof of that formula :3

The standalone b's cancel in (n - 1) · b + (b - n) and that's that.

ah right, nb-b+b-n is the same as nb-n. Didn't see that, thanks